the lateral surface of a cylinder is developed into a square whose diagonal is sqrt 5 cm . The area of the base of cylinder is?

• 0.1989 sq cm
  
  let the sides of the developed square be x cm long
  x^2+x^2=5
  x=sqrt(2.5)
  
  circumference of base of cylinder=2*pi*r
  2*pi*r=sqrt(2.5)
  r=sqrt(2.5)/(2*pi)
  area of base=pi*r^2=pi*[sqrt(2.5)/(2*pi)]*[sqrt(2.5)/(2*pi)]=2.5/4pi=0.1989 sq cm
  
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