In how many ways can 5 members be selected out of 10 members, so that any two particular members must always be excluded?

• here we have two exclude 2 from 10
  then the remaining members are 8
  we have to select 5 from 8
  the no of ways to select 5 from 8 are 8C5
  8*7*6*5*4/5*4*3*2*1=56
  ans:56 ways
• 8 years agoHelpfull: Yes(7) No(0)
• 2 members are excluded so 8c5
• 8 years agoHelpfull: Yes(2) No(0)
• 2 particular members are excluded so we have to select 5 out of 8 members .
  that is =8C5 =56
• 8 years agoHelpfull: Yes(2) No(0)
• ans is 56
  
  8c5=56
• 7 years agoHelpfull: Yes(1) No(0)
• direct formula
  (n-k)C(r-k)
  10-2C5-2
  8C3=56
• 7 years agoHelpfull: Yes(0) No(1)
• here , we have to select 5 members from 10 members, in that we have to exclude 2 particular members.
  
  so ways will be = 8c5 = 8c3 = [8*7*6]/[3*2*1] = 56.
• 2 years agoHelpfull: Yes(0) No(0)