3i-Infotech
Company
Numerical Ability
Area and Volume
How many rotations per minute must a wheel of diameter 1.5m make to achive a speed of 45kmph?(Approx pi=3)
Read Solution (Total 8)
-
- distance to be covered in 1 min.=(45*1000/60)m =750 m
circumference of wheel = 2*3*1.5/2 =4.50
number of revolutions per min. =(750/4.50) =166.67 - 8 years agoHelpfull: Yes(8) No(2)
- 1666.66 rpm
- 8 years agoHelpfull: Yes(1) No(0)
- distance covered in 1 minute = 45*1000/60
this distance is equal to distance covered in n rotations
distance covered in 1 rotation=circumference
pi*d*n=45*1000/60
n=167 - 8 years agoHelpfull: Yes(1) No(0)
- distance to be covered in 1 min.=(45*1000/60)m =750 m
circumference of wheel = 2*3*1.5/2 =4.50
number of revolutions per min. =(750/4.50) =166.67 - 8 years agoHelpfull: Yes(0) No(0)
- 45 kmph = 45x1000/60 m/min = 750m/min( U). U= pi DN or N=U/pi D = 750/3x1.5 = 166.66 rpm
- 8 years agoHelpfull: Yes(0) No(0)
- =1.5M SPEED =45KMPH Pi(Given)=3
R=1.5/2m=0.75m
circumference =
2xpixR
So,
2x3x0.75 =6x0.75=4.5rev/60 =0.075m/min
c= 0.075
for 45mph speed 45x0.075x100=3375rev/min
rotations per min =3375/60
approx 55 rev/min
No of rotations per min = 55 rev/min
No of rotations need to cover d= 55/4.5=12.22rotations
Therefore in 45mph whell need to take 12.22 rotations /min to cover 45mph - 7 years agoHelpfull: Yes(0) No(3)
- so here to solve this question, we have given the required speed which is 45km/hr.
so, distance covered by wheel in one minute= (45*1000*100)/60 cm= 75000 cm.
now we have to calculate circumference of the wheel= 2*pi*r = 2*3*75 cm= 450 cm
so number of rotations per minute= 75000/450 = 500/3 = 166.67 rotations per minute. - 2 years agoHelpfull: Yes(0) No(0)
- 45/1.5*3=10
- 2 years agoHelpfull: Yes(0) No(0)
3i-Infotech Other Question