Three disinct single-digit numbers A,B and C are in geomentric progrossion .If abs(x) for real x is the absolute value of x(x if x is positive or zero and -x if x is negative ).then the number of different possible values of abs(A+B-C) is

a) 3 b) 5 c) 6 d) 4

• As nos are in gp so let d 1st no be 1, 1×3,1×3^2
  Abs(x) =x (as x is positive no)
  Abs(1+3-9) = |1+3-9| = 5 , option (b)
• 8 years agoHelpfull: Yes(4) No(2)
• here it is asking different possible values of abs(A+B-C)
  2+4-6=0
  4+6-8=2
  3+6-9=0
  1+2-4=-1
  1+3-6=-2
  therefore 3 possible values
• 8 years agoHelpfull: Yes(3) No(4)
• a=1
  b=3
  c=9
  a+b-c=5
  ans is 5(b)
• 8 years agoHelpfull: Yes(2) No(3)
• (1,3,9) and (2,4,8) are different ways possible for this.....by taking this we can get answer as (1+3-9)=-5 and (2+4-8)=-2
  so only 2 values are possible
  No option and hence referred as dummy question
• 8 years agoHelpfull: Yes(0) No(5)