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if F(t)= (t^3-1)
G(t)= 1
H(t)= -t^2
then find the value of
FOHOG at t= -3
Read Solution (Total 16)
-
- -2 is the answer
- 8 years agoHelpfull: Yes(24) No(3)
- 1 is the answer.
- 8 years agoHelpfull: Yes(8) No(4)
- F()H()G(T)
F()H(G(T)) G(T)=1
F()H(1) H(1)= -1 * -1 = 1
F(1) F(-1)= 1^3 - 1= 1 - 1 = 0 - 8 years agoHelpfull: Yes(8) No(3)
- FOHOG(t)
FOH[G(-3)]
FOH[1]
F[H[1]]
F[1] =1-1 =0
- 8 years agoHelpfull: Yes(5) No(2)
- ans will be always 0 irrespective of t= -3
- 8 years agoHelpfull: Yes(2) No(1)
- 0 is the answer
- 8 years agoHelpfull: Yes(2) No(1)
- what is this oin between f and g?
- 8 years agoHelpfull: Yes(2) No(1)
- -2 is the answer not 0 see the value of h(t) carefully
- 7 years agoHelpfull: Yes(2) No(0)
- o is the answer
- 8 years agoHelpfull: Yes(1) No(5)
- 0 is correct 100%
- 8 years agoHelpfull: Yes(1) No(1)
- Ans is -2 because in -t^2 - should be taken after simplification of t^2
- 7 years agoHelpfull: Yes(1) No(0)
- f(h(g(t)))=f(h(1))
h(1)=-t^2=-1
f(-1)=(t^3-1)=-1-1=-2
so ans :-2 - 6 years agoHelpfull: Yes(1) No(1)
- plz explain how to do?
- 8 years agoHelpfull: Yes(0) No(0)
- f(h(g))=f(h(1))=1-1=0
so 0 is the answer - 8 years agoHelpfull: Yes(0) No(1)
- f(h(g(-3)))=f(h(1))=f(1)
substitute 1 in place of t
it gives u 1-1=0 - 8 years agoHelpfull: Yes(0) No(1)
- 0 is the correct answer
- 7 years agoHelpfull: Yes(0) No(0)
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