if F(t)= (t^3-1)
G(t)= 1
H(t)= -t^2

then find the value of
FOHOG at t= -3

• -2 is the answer
• 8 years agoHelpfull: Yes(24) No(3)
• 1 is the answer.
  
• 8 years agoHelpfull: Yes(8) No(4)
• F()H()G(T)
  F()H(G(T)) G(T)=1
  F()H(1) H(1)= -1 * -1 = 1
  F(1) F(-1)= 1^3 - 1= 1 - 1 = 0
• 8 years agoHelpfull: Yes(8) No(3)
• FOHOG(t)
  FOH[G(-3)]
  FOH[1]
  F[H[1]]
  F[1] =1-1 =0
  
• 7 years agoHelpfull: Yes(5) No(2)
• ans will be always 0 irrespective of t= -3
• 8 years agoHelpfull: Yes(2) No(1)
• 0 is the answer
• 8 years agoHelpfull: Yes(2) No(1)
• what is this oin between f and g?
  
• 8 years agoHelpfull: Yes(2) No(1)
• -2 is the answer not 0 see the value of h(t) carefully
• 6 years agoHelpfull: Yes(2) No(0)
• o is the answer
• 8 years agoHelpfull: Yes(1) No(5)
• 0 is correct 100%
• 7 years agoHelpfull: Yes(1) No(1)
• Ans is -2 because in -t^2 - should be taken after simplification of t^2
• 6 years agoHelpfull: Yes(1) No(0)
• f(h(g(t)))=f(h(1))
  h(1)=-t^2=-1
  f(-1)=(t^3-1)=-1-1=-2
  so ans :-2
• 6 years agoHelpfull: Yes(1) No(1)
• plz explain how to do?
• 8 years agoHelpfull: Yes(0) No(0)
• f(h(g))=f(h(1))=1-1=0
  so 0 is the answer
• 7 years agoHelpfull: Yes(0) No(1)
• f(h(g(-3)))=f(h(1))=f(1)
  substitute 1 in place of t
  it gives u 1-1=0
• 7 years agoHelpfull: Yes(0) No(1)
• 0 is the correct answer
• 6 years agoHelpfull: Yes(0) No(0)