Find the number of zeros in the expression 15*32*25*22*40*75*98*112*125

7
12
9
14

• answer is 9
  15-3*5
  32-2*2*2*2*2
  25-5*5
  22-2*11
  40-2*2*2*5
  75-5*5*3
  98-2*7*7
  112-2*2*2*2*7
  125-5*5*5
  here we will get 0 when 2 is multiplied by 5
  and total no. of 2's are-14 and 5's are- 9
  so no. of zeroes is according to 5 as it is minimum so ans is 9
• 8 years agoHelpfull: Yes(20) No(0)
• 9...because its factors involve 9 pairs of 5x2
• 8 years agoHelpfull: Yes(3) No(3)
• after multiply =1086624000000000
  count no. of zeroe's which are 9 .
  ans -9
• 8 years agoHelpfull: Yes(3) No(7)
• factor pairs of 5x2 in 15*32*25*22*40*75*98*112*125 is "9".......... so the ans is 9
• 8 years agoHelpfull: Yes(2) No(0)
• 7
  5*2 combimations
• 8 years agoHelpfull: Yes(0) No(2)
• Calculate number of 5's and number of 2's in each number given in the question that means take LCM of each number which gives you number of 2's and 5's
• 8 years agoHelpfull: Yes(0) No(0)
• how long the question is!!!! it doesn't matter. just fing the factors for each number and see the number of combination of 2's and 5's. here
  15=5*3
  32=2*2*2*2*2
  25=5*5
  22=2*11
  40=2^3*5
  75=5^2*3
  98=7^2*2
  112=2^4*7
  125=5^3
  here in total there are 9 pairs of 2*5, so the number of 0's are 9.
  
• 8 years agoHelpfull: Yes(0) No(1)
• No of zero depends upon no of Fives present as no of two is clearly going to be more than no of 5s.
  So the answer is 9.. as 15 have 1 no of 5, 25 has 2 no of 5s... and so on
  
• 8 years agoHelpfull: Yes(0) No(0)
• x1+x2+x3=13 wher x1,x2,x3>=1 and x1,x2,x3
• 7 years agoHelpfull: Yes(0) No(0)
• write every number into its prime factors form at last we will get 5^9 *2^13 *3^4 *11*7^2 .so no of zeroes will be equal to the power of 5 as no of 2's available are more than 5. so answer is 9
• 7 years agoHelpfull: Yes(0) No(0)