a drawer hold 4 red hates and 4 blue hates. what is the probability of getting exactly 3 when taking out 4 hates randomly out of the drawer and immediately returning every hate to the drawer before taking out the next?

• Sorry by mistake
  for red 1/2*1/2*1/2*1/2= 1/16
  for blue 1/2*1/2*1/2*1/2= 1/16
  ans= 1/16+1/16=1/8
• 8 years agoHelpfull: Yes(6) No(0)
• ans= 1/8
  for red 1/2+1/2+1/2+1/2= 1/16
  for blue 1/2+1/2+1/2+1/2= 1/16
  ans= 1/16+1/16=1/8
• 8 years agoHelpfull: Yes(4) No(5)
• Ans: 1/4
  
  as n(s)=4*4=16
  n(a)=4
  p(a)=a/16=1/4
• 8 years agoHelpfull: Yes(2) No(5)
• i go for C 1/2
  
  probability of taking a particular hat is 1/2 ( 4/8)
  
  Now assume we have 2 take 3 blues and 1 red
  
  P(BBBR) = (1/2)^4
  P(BBRB) = (1/2)^4
  P(BRBB) = (1/2)^4
  P(RBBB) = (1/2)^4
  total = 4 * (1/2)^4
  
  similarly with red
  
  thus the total is 2*4*1/16 = 8/16 = 1/2
  
  hope its clear..
• 8 years agoHelpfull: Yes(1) No(1)
• for red-->1/4*1/4*1/4=1/64
  for blue-->1/4*1/4*1/4=1/64
  ans=1/64+1/64=1/32
  i think this should be the ans..please correct me if i m wrong
• 8 years agoHelpfull: Yes(0) No(4)
• For red-->4/8*4/8*4/8=1/8
  for blue-->4/8*4/8*4/8=1/8
  ans=1/8+1/8=1/4
• 8 years agoHelpfull: Yes(0) No(1)