If a ladder is 10 m long and distance between bottom of ladder and wall is 6 m. What is the maximum size of cube that can be placed between the ladder and wall.
a. 34.28
b. 24.28
c. 21.42
d. 28.56

• First of all the data given is not correct, the lenght of the ladder is 100m and the distance is 60m. Then Answer will be 34.28.
  
  Now, Make a square of side x inside a right angled triangle of base 60 m , hypotnuse 100m and perpendicular 80 m (calculated). Square will create two right angles . Consider any angle say 'y' b/w hypotnuse and base.
  
  Then, tan y = x /60-x
  and in full triangle, tan y = 8/6
  
  Equate both - > x/60-x = 8/6
  
  answer is x = 34.28
• 8 years agoHelpfull: Yes(9) No(0)
• 8/6 = tan(y)
  x/6*10 -x =tan(y)
  
  8/6=x/60-x
  x=34.28
• 8 years agoHelpfull: Yes(6) No(0)
• ans will be 34.28
• 8 years agoHelpfull: Yes(3) No(0)
• ya cn u please explain it
• 8 years agoHelpfull: Yes(1) No(0)
• assumption is the cube is placed against the wall
  It should be 100m and 60m .. let height =a=60, hypotenuse=c=100, so base=b=80 the formula is (a*b)/(a+b)=34.28
• 6 years agoHelpfull: Yes(1) No(0)
• can you please explain SUSHOVAN MALLICK
• 8 years agoHelpfull: Yes(0) No(1)
• explain i cant understood plz
• 5 years agoHelpfull: Yes(0) No(0)