A and B income in the ratio of 5:4,and where expenditure in the ratio of 14:11 if they saves 1000 rs each then what is the total income of A?

• ANS: 15000
• 8 years agoHelpfull: Yes(8) No(0)
• 5x-1000/4x-1000=14/11 => x=3000. hence, Income of A = 5x = 5*3000 = 15000.
• 8 years agoHelpfull: Yes(5) No(1)
• income-expenditure=savings
  let As income=5x and Bs income=4x
  let As expenditure=14y and Bs expenditure=11y then we know that 5x-14y=1000-->(1) and 4x-11y=1000-->(2)
  on solving eqn1 and 2 we get x=3000 and y=1000
  hence As income is 5x=5*3000=15000.
• 6 years agoHelpfull: Yes(3) No(0)
• answer= income of A is 15000 rs
  For A
• 8 years agoHelpfull: Yes(0) No(0)
• Income of A=15000 rs
  For A
• 8 years agoHelpfull: Yes(0) No(0)
• ans= 15000
• 7 years agoHelpfull: Yes(0) No(0)
• 5x – 14y = 1000,
  also
  4x – 11y = 1000
  on solving x=3000
  so 5x-15000
• 6 years agoHelpfull: Yes(0) No(0)
• 15000
  IA/IB=5/4
  EA/EB=14/11
  IA-EA=1000
  IB-EB=1000
  IA=15000
• 6 years agoHelpfull: Yes(0) No(0)
• The answer is 15,000 rs
• 5 years agoHelpfull: Yes(0) No(0)
• 5x-14y=1000
  4x-11y=1000
  
  Solving two equation
  Y=1000
  So x=5000
  
  As income
  
  5x=15000
• 5 years agoHelpfull: Yes(0) No(0)
• 5x+1000/4x+1000=14/11
  11(5x+1000)=14(4x+1000)
  55x+11000=56x+14000
  x=3000
  total income of a is A=5*3000=15000
• 4 years agoHelpfull: Yes(0) No(0)
• 5x-1000 14
  -----------= -------
  4x-1000 11
  55x - 11000 = 56x - 14000 So income of A is 15000
• 4 years agoHelpfull: Yes(0) No(0)
• income of A= Rs.15000
  explain:
  let the income be x
  so A's income=5x B's income=4x
  let the expenditure be y
  so A;s expenditure=14y B;s expenditure be 11y
  they save Rs 1000
  5x-14y=1000 (1)
  4x-11y=1000 (2)
  on solving (1) and (2)
  x=3000 y=1000
  so A;s income=5x=5*3000=Rs 15000
• 4 years agoHelpfull: Yes(0) No(0)
• 5x-14y=1000
  4x-11y=1000
  after sloving
  x=15000
  income of a is 15000
• 4 years agoHelpfull: Yes(0) No(0)
• 5x-1000/4x-1000=14/11 => x=3000. hence, Income of A = 5x = 5*3000 = 15000.
• 9 Months agoHelpfull: Yes(0) No(0)