the difference of two ages is 35. 8 years ago one of the persons age is 6 times of other .then what is the sum of both ages

• 65 years
  
  x -y =35 ---(i)
  (x-8)= 6(y-8) or x-6y=-40 ---(ii)
  On solving (i) & (ii), x=50, y=15
  Sum of ages=x+y=50+15=65
• 8 years agoHelpfull: Yes(13) No(0)
• x-y=36
  x-8=6(y-8)
  slove we get 65
• 8 years agoHelpfull: Yes(3) No(3)
• let 1st person's present age be x.
  let 2nd person's present age be y.
  then,the difference of the two ages be,
  x-y=35
  
  8 years ago,
  1st person would be=x-8
  2nd person would be=y-8
  then,
  x-8=6(y-8)
  solving the two equations we will get,
  x=50 and y=15
  sum of both ages,
  x+y=65
  
• 8 years agoHelpfull: Yes(1) No(0)
• simply the equation would be (x+8) -(6x+8)=35 where x is the age before 8 years...when one's age was x and that of another's was 6x....now after 8 years their age will grow by 8 years respectively...and now the difference between their age is 35 ...so do the sum according the process given above...
• 8 years agoHelpfull: Yes(1) No(0)
• Ya 65 is the sum
  
• 8 years agoHelpfull: Yes(0) No(0)
• x-y=35 --> x=35+y
  x-8 = 6(y-8)
  35+y-8 = 6y-48
  5y = 75
  y=15
  x = y+35
  x=50
  x+y=15+50 =65 Ans
  
• 8 years agoHelpfull: Yes(0) No(0)
• 65
  n m , , ,
• 8 years agoHelpfull: Yes(0) No(0)
• Let the ages be x and y
  x-y=35
  x-8=6(y-8)
  on solving we get
  sum=65
• 8 years agoHelpfull: Yes(0) No(0)
• ans is 65..
• 8 years agoHelpfull: Yes(0) No(0)
• 65
  six years ago their ages is 6x,x
  now
  present ages 6x+8,x+8
  given that 6x+8-x-8=35
  so x=7
  then sum=65
• 8 years agoHelpfull: Yes(0) No(0)
• x-y=35
  x-8=6(y-8)
  on solving both we get
  x=50
  y=15
  hence x+y=65
• 8 years agoHelpfull: Yes(0) No(0)
• 65years .assume both the ages to be x and y and u will get two equations based on the conditions solving that will give u the ages
• 8 years agoHelpfull: Yes(0) No(0)
• 65 years
  
  x -y =35 ---(i)
  (x-8)= 6(y-8) or x-6y=-40 ---(ii)
  On solving (i) & (ii), x=50, y=15
  Sum of ages=x+y=50+15=65
• 8 years agoHelpfull: Yes(0) No(0)
• x-y= 35
  8 years ago, x=6y
  diff will remain same so from these two equation, we get x= 42 and y=7
  in present i.e after 8 year sum= (42+8)+(7+8)= 65
• 8 years agoHelpfull: Yes(0) No(0)
• x-y=35 then x=35+y
  x+8=6y+8
  35+y+8=6y+8
  35=5y
  y=7
  so x=35+7=42
  then x+y=42+7=49
  ans=49
• 8 years agoHelpfull: Yes(0) No(0)
• x-y=36
  x-8=6(y-8)
  slove answer is 50+15=65
• 6 years agoHelpfull: Yes(0) No(0)
• one is 15
  other is 50
  sum is 65
• 6 years agoHelpfull: Yes(0) No(0)
• (x-8)= 6(y-8) or x-6y=-40 ---(ii)
  On solving (i) & (ii), x=50, y=15
  Sum of ages=x+y=50+15=65
• 1 year agoHelpfull: Yes(0) No(0)