how many squares are there in series 2006,2013,2020,2027....2300?
hint-44^2=1936

a) 3
b) 4
c) 2
d) 1

• ans is 1
  
  as there r only 3 squares b/w 2006-2300 that are 45^2=2205, 46^2=2116, 47^2=2209
  now this series is an ap with 7 differnce.
  so the difference of these squares & 2006 must be a multiple of 7.
  only 2209-2006=203 which is multiple of 7.
  so correct ans is 1.
• 8 years agoHelpfull: Yes(10) No(0)
• ans-1
  as only 3no's square falls b/w the range those are45,46&47.
  and onlu 47's square falls in the series
  
• 8 years agoHelpfull: Yes(2) No(0)
• 1
  actually 3 but its a series wit difference 7..
• 8 years agoHelpfull: Yes(1) No(1)
• As the question is given in the A.P.so the common difference is 7 and first value is 2006.so we can write 2006+7K,
  45^2=1936+(2*45-1)=2025 (or,45^2=2025)
  46^2=2025+(2*46-1)=2116 (or,46^2=2116)
  47^2=2116+(2*47-1)=2209 (or,47^2=2209)
  in this question last value is 2300 .so we can not write 23^2.
  
  so, in this only 3 squares term are present so answer will be 3.
• 6 years agoHelpfull: Yes(1) No(0)
• a,b,c,d,e,f are the five real number in A.P and a is 4 times of c and sum of all is 3
  calculate value of e?
  option are
  9,-9,-3,-4
  plz solve this q
• 8 years agoHelpfull: Yes(0) No(0)
• What is the min.no.of questions are required to crack the tcs exam
• 8 years agoHelpfull: Yes(0) No(0)
• I attempted this question and my answer is wrong.. What will be the consequences?
• 8 years agoHelpfull: Yes(0) No(0)
• 45^2=2025
  46^2=2136
  47^2=2249, 48^2 =2364 exceeds the range
• 8 years agoHelpfull: Yes(0) No(0)
• 45^2;46^2;47^2-->in btween the given range so the answer is --->a
• 7 years agoHelpfull: Yes(0) No(0)
• d) 1
  Since, only 47^2 (2209) falls in the given series
• 6 years agoHelpfull: Yes(0) No(0)
• Answer is 3
• 4 years agoHelpfull: Yes(0) No(1)