A couple married in 1980 had two children, one in 1982 and the other in 1984. Their combined ages will equal the years of the marriage in?

a) 1986
b) 1985
c) 1987
d) 1988
e) 1989

• Option A-1986
  Sum of year = 1+9+8+0 =(18) 1+8 = 9
  1+9+8+2 =(20) 2+0 = 2
  1+9+8+4 = (13) 1+3 = 4
  Now 9+2+4= (15) 1+5= 6
  
  Nd option A 1+9+8+6 = 24(2+4)= 6
• 8 years agoHelpfull: Yes(11) No(4)
• IF 1986 IS THEIR PRESENT MARRIED YEAR 1986-1980=6
  IF 1st child is 4 year and 2nd one is 2 yrs old total 6
  6=6
• 8 years agoHelpfull: Yes(2) No(1)
• a)1986
  in this year two childs age equals=4+2=6
  marriage is equals to 6 years.
• 8 years agoHelpfull: Yes(2) No(1)
• Suppose the year value is 'x'.
  (x-1984)+(x-1982) = x-1980
  x = 1986
• 8 years agoHelpfull: Yes(0) No(0)
• option A is the correct ans . 1st child born on 1982 and the other on 1984 and combined ages of both the children will be equal to the no of years they got married so now we can go through options.
  In 1986 1st child age will be 4 yrs and the 2nd child age will be 2 yrs and there combined age will be(4+2=6) 6 yrs,and the couple got married in 1980 so in 1986 it is 6 yrs.
• 7 years agoHelpfull: Yes(0) No(0)