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20 litres of mixture of acid and water contain 10% water. How much water should be added so that percentage of water becomes 20% in this mixture?
a) 2 L
b) 3 L
c) 2.5 L
d) 4 L
Read Solution (Total 8)
-
- 2.5L is Exact answer...
because in 20 litres 2+18
for 22.5 litres 20% of water means 4.5+remaining 18 litres acid 80%........ - 8 years agoHelpfull: Yes(6) No(5)
- ans - a) 2 L
explaination )
total mixture =20ltr
water contain = 10% of 20ltr => 2ltr water
it means 18ltr is acid in that mixture
we have to make 20% water so..20% of 20 = 4ltr water must be there in the new mixture
we have already 2 ltr water so we have to add 2 ltr more
so ans => a)2ltr - 8 years agoHelpfull: Yes(4) No(5)
- ans-c)2.5
total mixture=20 ltr
water=20*(10/100)=2
let x ltr water should be added,
so (2+x)=(20+x)*(20/100)
=>(2+x)=(20+x)*5
=>x=2.5 ltr - 8 years agoHelpfull: Yes(3) No(1)
- Answer should be 2 l. H20 will be 2l and acid will be 4 l. Now consider water present in final solution as x. therefore, 18+x * 20/100 = x. solving for x, we get 4 l. Therefore, extra water added is 2 l.
- 8 years agoHelpfull: Yes(1) No(0)
- 10% of 20 litres is 2 litres.
To make it 20% water, you'll have to add 'x' litres of water to the mixture.
x+2/(x+20) = 20/100
5(x+2)=x+20
4x=10
x=10/4
x=2.5
So, if you add 2.5 litres of water to the mixture, you'll have 20% of water in the 22.5 litres of mixture. - 8 years agoHelpfull: Yes(1) No(0)
- in 20 litres it contains=2 ltrs water and 18 ltrs acid
to become 20% of water in mixture =20/2+x=4
x=3ltrs - 8 years agoHelpfull: Yes(0) No(6)
- 20lts=100%;
10%water remaing 90%acid.
10%=2lts
then 20%=2*2=4lts - 7 years agoHelpfull: Yes(0) No(0)
- d )4 L
10% of 20 litres is 2 litre of water
then 20 % of water is 4L - 7 years agoHelpfull: Yes(0) No(0)
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