The difference between compound interest and simple interest on a sum for 3 years at 10% p.a. is Rs.124 Find the sum.

a) Rs.5000
b) Rs.4000
c) Rs.6000
d) Rs.8000

• For 3 years, we know
  C.I-S.I= p(R/100)^3+3(R/100)^2
  so, putting all values we have,
  124=p((10/100)^3+3(10/100)^2)= 4000
• 8 years agoHelpfull: Yes(2) No(1)
• formula- C.I=[p(1+R/100)^n]-p;
  S.I=p*r*t/100;
  given that C.I-S.I=124
  r=10
  n=3
  put the values
  [p(11/10)^3-p]- p*10*3/100=124
  (1331p/1000 -p) -3p/10=124
  (331p/1000 ) - 3p/10=124
  31p/1000=124
  so p=(124*1000)/31
  so p=4000
  ans-B
• 8 years agoHelpfull: Yes(1) No(0)
• series X,O,I,F,?
  a) D b) E c)F d)B
  asked in techmahindra
• 8 years agoHelpfull: Yes(0) No(0)