An oil of Rs.42 per kg is mixed with 10 kg oil of Rs.69 per kg. If price of mixture oil is Rs.60 per kg then what is the quantity of first type of oil in the mixture?

a) 6 kg
b) 5 kg
c) 8 kg
d) 4 kg

• ans - b)
  let X be the first type of oil
  ((x*42)+(10*69))/(x+10)=60 by solvig the equation we get x=5
• 8 years agoHelpfull: Yes(8) No(1)
• ANSWER : 5(B)
  use allegation and mixture concept
  42 69
  60
  9(69-60) 18(60-42)
  
  so.. 1st:2nd ==> 9:18 ==> 1:2 . so if second is of 10 liters then first one will be of 5 liters.
• 7 years agoHelpfull: Yes(4) No(0)
• Rule of Mixture
  (Quantity of cheaper/Quantity of dearer)=(C.P fo dearer)-(mean price)/(mean price)-( C.P of cheaper)
  let quantity of cheaper=x
  Quantity of dearer=10 kg
  C.P fo dearer=69
  mean price=60
  C.P of cheaper=42
  x/10 =(69-60)/(60-42)
  x/10=9/18
  x=90/18
  so x=5kg
  Ans=B
  
• 7 years agoHelpfull: Yes(0) No(0)