If the difference between compound interest(interest compounded yearly) and simple interest on a sum for 3 years at 20% p.a. is Rs.132, then the sum is

a) Rs.3500
b) Rs.1500
c) Rs.2500
d) Rs.3000
e) None

• C.I-S.I=132
  C.I=A-P
  A=P(1+(R/100))^n
  A=x(1+(20/100))^3
  A=x(6/5)^3
  A=216/125(x)
  C.I=(91/125)x
  S.I=(PNR)/100=(x*3*20)/100=(6/10)x
  diff=132
  diff=(91/25)x-(6/10)x=(182x-150x)/250=32x/250
  32x/250=132
  x=(132*250)/32
  x=1031.25
• 8 years agoHelpfull: Yes(6) No(0)
• none of this
  if 132 is replaced by 192 ans is 1500
• 8 years agoHelpfull: Yes(4) No(0)
• Difference = p(r/100)n
  132=p(20/100)3
  =p(1/5)3
  p= 132*5*5*5 = 16,500
  
  Pls tell me ans s crct or wrng
  
  
• 8 years agoHelpfull: Yes(3) No(4)
• CI for 1500=1032
  SI for 1500=900
  diff=1032-900=132
• 8 years agoHelpfull: Yes(1) No(0)
• difference between CI-SI FOR 3 YEARS IS SUM = 10^6 XD(DIFFERENCE)/R^2(R+300) R=RATE
  SUM = 10^6 X132/400(10+300)
  =10^6 X132/ 400(320)
  =10000
  
• 8 years agoHelpfull: Yes(0) No(0)
• e) None
• 8 years agoHelpfull: Yes(0) No(0)
• none --- 1031.25
  let assume sum is P
  S.I = PTR/100
  C.I = P(1+R/100)^n - P
  The difference b/w C.I - S.I = P(1+R/100)^n - P - PTR/100
  we can solve this equation we get the sum value is 1031.25
• 8 years agoHelpfull: Yes(0) No(0)
• here SI-CI=132,R=20%
  WE KNOW THAT SI-CI=PR^2/100^2
  132=P*20*20/10000
  P=800 E
  
• 8 years agoHelpfull: Yes(0) No(0)