A man is three (3) years older than his wife and four (4) times as old as his son. If the son attains an age of fifteen (15) years after three (3) years, what is the present age of the mother?

a) 60 years
b) 51 years
c) 48 years
d) 45 years
e) 65 years

• 45 years
  Let mother age be x
  Father age be x+3
  X+3=4×12
  X=45
• 8 years agoHelpfull: Yes(15) No(1)
• m = w+3
  m = s* 4
  w +3 = s*4
  w + 3 = 15 * 4
  w +3 = 60
  w = 60-3
  w = 57
  after 3 years means 57 +3
  = 60
  so option A is correct
• 8 years agoHelpfull: Yes(4) No(6)
• 45 years. let x be age of son.
  man=3+wife age = 4x,
  after 3 years, x+3=15,x=12.
  3+wife age=12*4
  present ,wife age=45
  after 3 year, 48 years
• 8 years agoHelpfull: Yes(4) No(3)
• as 3 yr later sons will 15 yr
  so we can write
  Father's present age is 4(15-3)=48 yr
  So mother present age will be 48-3=45 yr
• 8 years agoHelpfull: Yes(4) No(0)
• age of after 3rs= 15
  presnt age of son is 12
  therefore age of father at present is =12*4=48
  mother age =48-3
  =45yrss
• 8 years agoHelpfull: Yes(1) No(0)
• i think A 60yrs is ans
  
• 8 years agoHelpfull: Yes(0) No(7)
• m=w+3
  m=4s
  m+3=4(s+3) ;;;;;;;s=15
  m+3=4s+12
  m+3=60+12
  m=69
  w=69-3
  w=65
  so wife age is 65
• 8 years agoHelpfull: Yes(0) No(7)
• given that father is 3 years older than his wife
  f=w+3;
  where we want to find out mothers present age
  let it be x.
  f=X+3
  x+3=4*(15-3)
  x=45
  
• 8 years agoHelpfull: Yes(0) No(0)