Ten years ago A was half of B’s Age. If ratio of their present ages is 3:4 then what is the total of their present ages?

a. 30 years
b. 08 years
c. 35 years
d. 20 years

• present age of A= 3x
  present age of B= 4x
  10 years ago A was half of B's age
  3x-10=1/2(4x-10)
  2x=10
  x=5
  total of their present age
  A=3x=3*5=15
  B=4x=4*5=20
  toatal present age=35yrs
• 8 years agoHelpfull: Yes(9) No(0)
• Option: C
  Lets say ten years ago A was half of B's age so,take 5 : 10
  Now,after 10 years A is 15 and B is 20
  15:20 is 3:4 so,combined age is 15+20 = 35
• 8 years agoHelpfull: Yes(4) No(2)
• let say present age of A and B is 3x and 4x
  
  before 10 years 3x-10 i.e A,s age and 4x-10 is b,s age
  
  accn to d ques .5(4x-10)=3x-10 sloving dis we get a=15 and b=20
  
• 8 years agoHelpfull: Yes(2) No(1)
• C) 35 years
  Present ages of A and B are 3x,4x
  Ten year's ago A was half of B's age x+10 = 2x+10 => x=5
  present ages are 3*5,4*5 = 15,20
  So total age is 15+20 = 35 years
• 8 years agoHelpfull: Yes(0) No(0)
• Go with options ---ans must divisible by 7x hence 35
• 6 years agoHelpfull: Yes(0) No(0)