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Numerical Ability
Time Distance and Speed
A can run 3 Kms in 3 min 18 sec and B can run same distance in 3 min 40 sec, then by how much distance A can beat B?
a. 300 m
b. 220 m
c. 280 m
d. 195 m
Read Solution (Total 9)
-
- Distance travelled=3000m
Time taken by A=3 m 18 s
Time taken by B=3 m 40 sec=220 sec
speed of B=3000m/220 s=150/11 m/s
Difference between time of A and B=22 sec
when time will be 3 m 18 s A will have travelled 3000m but B need 22 sec more to finish.
Distance travelled by B in 22 sec=(150/11)*22=300 m
Hence, A beat B by 300 m. - 8 years agoHelpfull: Yes(26) No(2)
- A 198 sec --> 3000 mtrs (3km)
B 220 sec --> 3000 mtrs(3km)
198 sec--> x mtrs
x*220=3000*198
x=300*9
x=2700
B can run 2700 mtrs in 198 sec
A-B=>3000 - 2700=>300 mtrs - 8 years agoHelpfull: Yes(20) No(0)
- 3km=3000m
difference is 22 second
3 min 40 s== 220 sec
so, 3000*22/220==300 ans - 8 years agoHelpfull: Yes(10) No(4)
- B can cover 3000m in 220sec
A can cover 3000m in 198sec
--> B can cover x m in 198sec
3000m --> 220sec
x m -->198sec
x=2700
difference=3000-2700=300m
ans is 300m
- 8 years agoHelpfull: Yes(6) No(0)
- please xplain clearly
- 8 years agoHelpfull: Yes(1) No(2)
- 3 min 40 sec = 220 sec
3min 18 sec = 198sec
time diff = 22 sec
dist=3000m
dist/time =3000/220=150/11
so in the additional 22 seconds B lacks behind by 300m - 8 years agoHelpfull: Yes(0) No(0)
- 3kms=3000m
3min 40 sec=3*60+40=220sec
3min 18sec=3*60+18=198sec
therefore D=?
we know that dis =3000m
so
3000/220*198=2700
SOLUTION:3000m-2700m=300m
distance that A can beat B is 300m - 8 years agoHelpfull: Yes(0) No(0)
- 3000---------198sec-->A
3000---------220sec-->B
198 sec both travel then for 22 sec of bis travel =300mts - 8 years agoHelpfull: Yes(0) No(0)
- 300
speed of A=3000/198 m/s
speed of B=300/220 m/s
difference in time to cover same distance= 40-18=22sec
distance travelled by B in 22 sec=(3000/220)*22=300 m - 6 years agoHelpfull: Yes(0) No(0)
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