How many members are there between 1 to 100 which are divisible by 9 and the sum of two digits is 9?

a. 13
b. 7
c. 11
d. 9
e. 10

• ans is e
  there are 11 numbers divisible by 9.
  But in number 99,
  9+9 is not equal to 9.
  so,the ans is 10 numbers
• 8 years agoHelpfull: Yes(18) No(8)
• In the question it is given that the sum of two digits should be 9 therefore- 18,27,36,45,54,63,72,81,90 total is 9.
  9 and 99 cannot be taken.
  Answer d
• 8 years agoHelpfull: Yes(16) No(4)
• There are 11 numbers between 1 to 100 which are divisible by 9 (9,18,27,36,45,54,63,72,81,90,99) so the ans is e coz 9+9 is not equal to 9
• 8 years agoHelpfull: Yes(8) No(2)
• 18,27,36,45,54,63,72,81 only these numbers sum is 9 so answer is 9 numbers
• 8 years agoHelpfull: Yes(3) No(8)
• 9 can be written as 09.
  So the answer is 10.
• 8 years agoHelpfull: Yes(3) No(0)
• 0-9 so 10
  1-8
  2-7
  3-6
  4-5
  5-4
  6-3
  7-2
  8-1
  9-0
• 8 years agoHelpfull: Yes(1) No(0)
• ans is 9.
  99/11=9
• 8 years agoHelpfull: Yes(0) No(0)
• e,0+9,1+8,2+7,3+6,4+5,5+,6+3,7+2,8+1,9+0
• 8 years agoHelpfull: Yes(0) No(0)
• as the queston mention that the divisible no is a 2 digit no which is only d case when 9 is multiply to 1 to 11 .But in case of 11 ,9*11=99 and 9+9=! 9.violate the 2nd condition of the problem.therefore ans is option (e)
  
• 8 years agoHelpfull: Yes(0) No(0)