The age of a father is 5/2 of his daughter. 5 years ago it was 3 times that of his daughter.what is daughter's present age?

(a) 20YRS
(b) 25YRS
(c) 15YRS
(d) 10YRS

• daughter's present age is x
  father's present age is (5/2)*x
  5 years ago father's age is (5x/2)-5=3(x-5)
  Therefore,x=20 years
  so, ans is a.
• 8 years agoHelpfull: Yes(24) No(2)
• F=5/2(d)
  F-5=3(d-5)
  (5/2)d-5=3d-15
  5d-10=6d-30
  D=20
• 8 years agoHelpfull: Yes(2) No(0)
• 5 years ago her age was 20.
  So her present age become 20+5 =25...
• 8 years agoHelpfull: Yes(1) No(5)
• daughter's present age is x
  father's present age is (5/2)*x
  5 years ago father's age is (5x/2)-5=3(x-5)
  Therefore,x=20 years
  
• 8 years agoHelpfull: Yes(1) No(0)
• present ages x:5x/2
  3(x-4)=5x/2-4
  3x-12=(5x-8)/2
  6x-24=5x-8
  x=16
• 8 years agoHelpfull: Yes(0) No(7)
• 20
  5/2x-5=3(x-5)
  5x-10=6x-30
  x=20
• 8 years agoHelpfull: Yes(0) No(0)
• here f=5d/2;
  f-5=3(d-5)
  5d/2-5=3d-15
  5d-6d/2=10
  d=20;
• 8 years agoHelpfull: Yes(0) No(0)
• option-a
  f=5/2(d)
  f-5=3(d-5)
  by solving 2 equations we get d=20
• 8 years agoHelpfull: Yes(0) No(0)
• Present age's of father and daughter are 2.5x , x
  5 year's ago it was three times, 2.5x+5 = (x+5)3
  0.5x = 10
  x = 100/5 = 20 years
• 8 years agoHelpfull: Yes(0) No(0)