At what rate of interest (compounded yearly)will Rs.10,000 amount to Rs.12100 in 2 years?

(a) 9%
(b) 11%
(c) 8%
(d) 10%

• (d) 10%
  
  If rate=r, then 10000[1+(r/100)]^2 =12100 ,(100+r)^2 /100^2 =121
  r^2 +200r -2100=0
  (r-10)(r+210)=0
  r=10
• 8 years agoHelpfull: Yes(15) No(3)
• (1+R/100)^2=121/100=(11/10)^2
  thats why 1+R/100=11/10
  thats why r=10%
• 8 years agoHelpfull: Yes(10) No(0)
• Ans is 10 by using formula
• 8 years agoHelpfull: Yes(0) No(0)
• Take 2100/10000=21℅
  For 2 yrs so take 20/2=10%
  Extra 1%is compounded interest
  So ans 10%
• 8 years agoHelpfull: Yes(0) No(0)
• P = 10000
  CI= 12100
  n = 2
  R = ?
  CI = P( 1+ R/100)^n
  12100 = 10000( 1+ R/100)^2
  121 = 100 {(100+R) / 100 }^2
  121/100 = {(100+R) / 100 }^2
  (11/10)^2 = {(100+R) / 100 }^2
  (11/10) = (100+R) / 100
  R = 10% -Ans
• 8 years agoHelpfull: Yes(0) No(0)
• option d) 10%
• 7 years agoHelpfull: Yes(0) No(0)