A train started from station 'A' and proceeded towards station 'B' at a speed of 48 Km/hr. Forty-five minutes later another train started from station 'B' and proceeded towards station 'A' at 50 Km/hr. If the distance between the two stations is 232 Km, at what distance from station 'A' will the trains meet?

(a) 160KM
(b) 108KM
(c) 132KM
(d) 144KM

• Train A started 45 min ago,by the time train B started,
  It means Distance covered by the Train A in 45 min is 48*45/60=36km covered,
  now remaining distance=196km
  since they are moving towards each other relative speed=48+50=98kmph
  and time=196/98=2hrs
  In 2hrs trainAcovered 96km distance and 36 km already covered
  =>96=36=132km
  Hence,132 km from station A, trains meet eachother.
  
• 8 years agoHelpfull: Yes(42) No(4)
• Distance between A and B =232
  Distance covered by A and B is,
  (48*x)+(50*(x-(45/60)))=232
  Therefore, x=11/4
  so,distance covered by A is,
  48*x=48*(11/4)=132km
  
  So,ans:c
• 8 years agoHelpfull: Yes(18) No(2)
• A's speed-48km/hr.
  B's speed-50km/hr.
  A's start 45 min before of B's, so distance covered by A=> 48=x/(3/4) (45 min in rational).
  x=36KM.
  232-36=>196=(48+50)*t, =>196/98=t, =>t=2.
  A's speed 48*t=distance, =>96+36(previous covered), =>132KM.
• 8 years agoHelpfull: Yes(4) No(0)
• They will meet when sum of the distance covered by them is 232 km
  
  suppose they meet after t hr of departure time at A
  
  then travelling time of B will be t-3/4 hrs
  
  DA=48t
  
  DB=50(t-3/4)
  
  DA +DB= 48t + 50(t-3/4)=232
  
  solving we get t=11/4 hrs
  
  distance from A= 48x11/4=132 km
  
• 8 years agoHelpfull: Yes(2) No(0)
• suppose they will meet each other after t hrs at a
  time taken by b to reach hat distance is t-34
  da+db=48t+50(t-34)
  t=114 therefore 48(114)=132
  they will meet after 132 kms from a
  
• 8 years agoHelpfull: Yes(1) No(0)
• 108km ; 232-(3/4 *48) = 232-36 =196; 196/(48+50)= 2hrs ; 36+(2*48)=108
  
• 8 years agoHelpfull: Yes(0) No(2)
• c is the correct answer
• 8 years agoHelpfull: Yes(0) No(0)