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Numerical Ability
Age Problem
Fathers age is 5 times his son's age. 4 years back the father was 9 times older than son.Find the fathers' present age.
(a) 41
(b) 40
(c) 39
(d) 45
Read Solution (Total 27)
-
- fathers age =x sons age =y
x=5y;x-4=9(y-4)
5y-4=9y-36
y=8 so x=40 - 8 years agoHelpfull: Yes(34) No(1)
- Let's son age=x
Father's age is five times of son=5x
Fours years back,
Son=x-4
Father=5x-4
Given in qstn
F=9(x-4)
5x-4=9x-36
X=8
Therefore father's age=5*8=40 - 8 years agoHelpfull: Yes(10) No(0)
- let son's age is "x" and father's will be "5x"
4 years back father's age is 9 means the eq is
5x-4=9(x-4)
5x-4=9x-36
4x=32
x=8
hence father's age is 5*8=40 - 8 years agoHelpfull: Yes(3) No(0)
- use elimination process of given choices
lets take 40 as fathers age then sons age is 8
4 years back means fathers age is 36 and sons age is 4 which is equal to 9 times of fathers age - 8 years agoHelpfull: Yes(2) No(1)
- Father's age=f
son's age=s
f = 5s
(f-4) = 9(s-4)
=>f-4=9s-36
=>5s-4=9s-36
=>32=4s
=>s=8
=>f=40 - 8 years agoHelpfull: Yes(1) No(0)
- let x=father's age and y= son's age
x=5y
now 4 year's back
x-4=9*(y-4)
x=9y-36
substitute the value of x from above equation
5y=9y-32
y=8
and
x=40
so 40 is correct answer - 8 years agoHelpfull: Yes(1) No(0)
- 40. At present x = 5x and 4 years back the age of father was 9y = y and x-4= 5x -4 .we get two eq i.e x-4 = y and 5x-4=9y. Solve it . we get ans is 40
- 8 years agoHelpfull: Yes(1) No(0)
- ans:40 years
son present age=x
father present age=5x (bcoz father is 5 times his SON'S AGE)
now 4 years back...
SON FATHER
9(x-4) = (5x-4) //father was 9 times older than son so, 9(sons age)= father age 4 years back..
9x-36 = 5x-4
9x-5x = 36-4
4x = 32
x = 8
so, father present age=5x i.e., 5*8=40 - 8 years agoHelpfull: Yes(1) No(0)
- Let son present age x
So father's present age 5x
4 yr ago father's was 9 times of son's age
So we may write
9(x-4)=(5x-4)
X=8
So father age will be 5x=5*8=40 - 8 years agoHelpfull: Yes(1) No(0)
fathers age =x sons age =y
x=5y;x-4=9(y-4)
5y-4=9y-36
y=8 so x=40
- 8 years agoHelpfull: Yes(0) No(0)
- option verification
- 8 years agoHelpfull: Yes(0) No(0)
- x = father's age
y = son's age
x = 5y
x-4 = 9(y-4)
x-4 = 9y-36
x = 9y-32
5y = x = 9y-32
5y = 9y-32
4y = 32
y = 8
x = 5y = 40
- 8 years agoHelpfull: Yes(0) No(0)
- 40Ans
F=5s ----(1)
F-4=9(S-9) - 8 years agoHelpfull: Yes(0) No(0)
- Present: F = 5 * S;
Four Years back: F - 4 = 9*(S-4);
by solving the above two equations we get S =8 and F = 40 - 8 years agoHelpfull: Yes(0) No(0)
- Fathers present age is 40
answer
Given father = 5* son
father-4 =9(son-4)
solving the two equations you will get father age=40 - 8 years agoHelpfull: Yes(0) No(0)
- present age of son and father = x : 5x
5x-4 = 9(x-4)
5x-4=9x-36
4x=32
x=8
so present age of father is 40
- 8 years agoHelpfull: Yes(0) No(0)
- Father=5*son----------------->1
Before 4 years
Father-4=9(son-4)
5*son)-4=9*son-36
36-4=9son-5son
4son=32
Son=8years
Father=5*son==>40years
So answer is 40years
- 8 years agoHelpfull: Yes(0) No(0)
- Option b is correct 40
- 8 years agoHelpfull: Yes(0) No(1)
- Son's age = x
Father's age is 5 times son's age = 5x
4 years back
F's age = 5x-4
Where he is 9times older than son
5x-4 =9 (x-4)
X=8
Father present age is 5x
5*8=40 - 8 years agoHelpfull: Yes(0) No(0)
- ATP
RaTIOS ARE
5:1 and 9:1
SO Balancing the ratios we get
40:8 and 36:4
difference is 4 so 4/4=1
so father present age is 40 yrs and son is 8 yrs
- 8 years agoHelpfull: Yes(0) No(1)
- son=x;
father=5x;
4 yrs back their ages
son=x-4;
father=5x-4;
A/c-
9(x-4)=5x-4
x=8;
father=5x8=40 yrs - 8 years agoHelpfull: Yes(0) No(0)
- Father's age-f, Son's age-s
present-f=5s.
4 yrs back->f-4=(s-4)9.
=>5s-4=9s-36 (replace with present)
4s=32, =>s=8
f=5s, => 40 Ans
- 8 years agoHelpfull: Yes(0) No(0)
- f=5s
f-4=9(s-4)
by solving above equations we get f=40 - 8 years agoHelpfull: Yes(0) No(0)
- b , (x-4)=9(y-4)
5y-4=9y-36
4y=32
y=8
x=5y=40 - 8 years agoHelpfull: Yes(0) No(0)
- 40
y=5x (Age of father:y,age of son:x)
y-4=9(x-4)
solving, x=8,
father's present age=5x=5*8=40 - 8 years agoHelpfull: Yes(0) No(0)
- B) 40
present ages X,5X
4 years ago father's age was 9 times older than son 9(x+4)=5x+4
9x+36=5x+4
4x=32
x=8
5(8)=40 - 8 years agoHelpfull: Yes(0) No(0)
- Let the present age of father be F and son be S
So from 1St condition
F= 5 S
Four year back
(F-4 )= 9 (S-4)
S= 8 Year
Therefore F= 40 - 7 years agoHelpfull: Yes(0) No(0)
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