Find the number of perfect squares in the given series 2013, 2020, 2027,................, 2300
(Hint 44^2=1936)

• only 1 perfect square
• 8 years agoHelpfull: Yes(9) No(2)
• there are 3
  2025=45*45
  2116=46*46
  2209=47*47
• 8 years agoHelpfull: Yes(6) No(21)
• ans is 1, because the series has difference 7..so 47^2 only satisfy these series.
• 8 years agoHelpfull: Yes(5) No(1)
• Only one perfect square and which is 47×47
• 8 years agoHelpfull: Yes(5) No(1)
• The given series is an AP with common difference of 7. So the terms in the above series are in the form of 2013 + 7k. We have to find the perfect squares in this format in the given series.
  Given that 44^2 = 1936.
  Shortcut: To find the next perfect square, add 45th odd number to 44^2.
  So 45^2 = 1936 + (2 x 45 -1) = 2025
  46^2 = 2025 + (2 x 46 - 1) = 2116
  47^2 = 2116 + (2 x 47 - 1) = 2209
  Now subtract 2013 from the above numbers and divide by 7. Only 2209 is in the format of 2013 + 7k. One number satisfies.
• 7 years agoHelpfull: Yes(5) No(2)
• ya,i got it.it ll be on 17th march on tcs office Chennai.
  
• 8 years agoHelpfull: Yes(1) No(6)
• guys anyone got their schedule for 2nd march 2016 off campus written exam...?
  
• 8 years agoHelpfull: Yes(0) No(8)
• 2293
  Bacause each square no. Is added by 7
  
• 8 years agoHelpfull: Yes(0) No(0)
• 2
  45*45=2025
  46*46=2116
• 8 years agoHelpfull: Yes(0) No(1)
• ans is 3
• 7 years agoHelpfull: Yes(0) No(0)
• Can anyone explain wat to prepare for coding round
• 7 years agoHelpfull: Yes(0) No(0)
• only 1 i.e. 47^2 = 2207
• 6 years agoHelpfull: Yes(0) No(0)
• Answer: a
  Explanation:
  The given series is an AP with common difference of 7. So the terms in the above series are in the form of 2013 + 7k. We have to find the perfect squares in this format in the given series.
  Given that 44^2 = 1936.
  Shortcut: To find the next perfect square, add 45th odd number to 44^2.
  So 45^2 = 1936 + (2 x 45 -1) = 2025
  46^2 = 2025 + (2 x 46 - 1) = 2116
  47^2 = 2116 + (2 x 47 - 1) = 2209
  Now subtract 2013 from the above numbers and divide by 7. Only 2209 is in the format of 2013 + 7k. One number satisfies.
• 4 years agoHelpfull: Yes(0) No(0)