x-1-x=5-then-x-4-3x-3-5x-2-3x-1-x-4-1

• we have,
  x-1-x=5
  1-1/x-1=5/x
  1/x+5/x=0
  x/1+x/5=0
  6x/5=0
  x=0
  then
  given that
  -x-4-3x-3-5x-2-3x-1-x-4-1
  putting value of x then
  -15
• 8 years agoHelpfull: Yes(2) No(1)
• x-1-x=5
  x(1-1/x-1)=5
  x(x-1-x)=5x
  x^2-x-x^2=5x
  cancelling x^2 we get -x=5x
  6x=0
  so x=0
  now -x-4-3x-3-5x-2-3x-1-x-4-1= -13x-20
  =0-20
  = -20
• 8 years agoHelpfull: Yes(1) No(3)