In a swimming pool two swim in opposite direction there first meeting is 50m long from east of swimming pool and second meeting is 30m long from west of swimming pool then length of swimming pool?

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  swimmer.
  
  In the first leg she swam 50m
  , so in the 2nd leg she must have swum 100m
  
  In the 2nd leg, she swam L−50+30,
  
  so equating
  
  L−50+30=100
  , which yields L=120m
  hope this is correct..
• 8 years agoHelpfull: Yes(7) No(3)
• http://math.stackexchange.com/questions/1489277/find-the-length-of-the-pool-given-the-following-conditions
  
• 8 years agoHelpfull: Yes(4) No(1)
• W|----------------------->~~~~~~~~|
  |==30 = ===50===|
  |~~~~~~~~~~~~~
• 8 years agoHelpfull: Yes(0) No(0)
• here in above question they have given that speed is constant
• 8 years agoHelpfull: Yes(0) No(0)
• By taking lcm of 50 and 30
  i.e lcm(30,50) = 150 m
  
• 8 years agoHelpfull: Yes(0) No(1)
• simply length=50+30=80m
  because speed will be different of swimmers but length will not vary.
  
• 8 years agoHelpfull: Yes(0) No(2)