A passenger train runs at the rate of 80 kmph. It starts from the station at some time. After 6 hours a goods trains leaves the station. The passenger train overtakes the goods train after 4 hours. The speed of goods train is:

• How passenger train can overtake goods train, if it is running ahead of goods train.
  I think there should be an interchange in 'passenger train' and 'goods train' in the question.
  Considering speed of goods train=80 kmph, distance covered in 6 hrs=80*6=480 km.
  If passenger train has a speed=x kmph, then relative speed=x-80
  So to cover-up a difference of 480 kms in 4 hrs, 480/(x-80) =4, x=200
• 8 years agoHelpfull: Yes(5) No(0)
• total pasenger train time= 6+4=10 so
  total distance 80*10=800
  so goods train speed is 800/4=200 KM/Hr
• 8 years agoHelpfull: Yes(3) No(0)
• Let the speed of goods train = x kmph.
  Time difference between the trains = (6+4)=10hrs.
  So, distance (D) covered by goods train in 10 hrs = Distance covered by passenger train in 4 hrs.
  Distance = Speed * Time
  
  10x = 4*80
  10x = 320
  x= 32kmph.. Speed of the goods train.
• 8 years agoHelpfull: Yes(2) No(6)
• ans is200. 6+4=10. 10*80=800, 800/4=200
• 7 years agoHelpfull: Yes(0) No(0)
• S1×T1=S2×T2
  S2=(80×4)÷10=32
• 6 years agoHelpfull: Yes(0) No(0)