17. A, B, C, D and E are five consecutive odd numbers. The sum of A and C is 146. What is the value of E?

• E=79
  
  As A,B,C,D & E are five consecutive odd numbers ,where B=A+2, C=A+4, D=A+6, E=A+8
  Given A+C=146, As C=A+4, so 2A+4=146 or A=71
  So value of E=79
• 8 years agoHelpfull: Yes(1) No(0)
• lets take A as x so C is x+2, so x+x+2=2x+2=146, i.e 2x=144,
  So x=72. So since E is x+4 so E is 76.
• 8 years agoHelpfull: Yes(0) No(1)
• Consecutive odd numbers A=x+1,B=x+3,C=x+5,D=x+7,E=x+9 ,
  A+D=x+1+x+5
  2x+6=146
  2x=140=>x=70
  E=x+9=>70+9=>79
• 8 years agoHelpfull: Yes(0) No(0)
• Consider a to be x and the sequence will be like x x+2 x+4 x+6 and so on
  Given a+c = 146.
  That is x+x+4= 146
  2x = 142 and x is 71
  Thus sequence is 71 73 75 77 79
  And hence E is equal to 79
• 8 years agoHelpfull: Yes(0) No(0)
• E= 79
  let the 5 no's be n,n+2, n+4,n+6,n+8 = A, B, C, D, E respectively.
  A+C= n+n+4= 2n+4=146
  n=71
  so, E=79
  
  
• 8 years agoHelpfull: Yes(0) No(0)
• X + (X+2) + (X+4) + (X+4) + (X+6) + (X+8)
  Now X + (X+4) = 146 given
  So X = 71
  Value of E is 79.
• 7 years agoHelpfull: Yes(0) No(0)
• answer is 79.
• 7 years agoHelpfull: Yes(0) No(0)