working together rajeev and vikram can complete a piece of work in 48 days.rajeev can complete the work alone in 64 days. both of them work together for 30 days and then rajeev left.how long will vikram take to complete the remaining work?

• 72 days
  
  If Vikram alone can complete the work in 'x' days, then their 1 day work=(1/64)+(1/x)=1/48
  1/x=(1/48) -(1/64)=1/92
  So 30 days work of Rajeev & Vikram=30*(1/48)=5/8, Remaining work=3/8
  Days required for Vikram to complete remaining work=(3/8)/(1/192)=72
• 8 years agoHelpfull: Yes(4) No(7)
• This problem can be done using lcm concept
  quantity of work to be done=lcm(64,48)=192units
  work done by rajeev and vikram=192/48=4units/day
  work done by rajeev =192/64=3units/day
  so work done by vikram=4-3=1units/day
  work done by rajjev and vikram in 30 days=30*4=120units
  Remaining work to be done by vikram=12-120=72units
  so time taken by vikram to complete 72 units=72/1=72days
• 7 years agoHelpfull: Yes(4) No(1)