1/3 rd of the contents of a container evaporated on the 1st day. 3/4th of the remaining contents of the container evaporated on the second day.
What part of the contents of the container is left at the end of the second day?

• After first day only 2/3rd remains. After second day only 1/4th of that remaining from 1st day remains. So, final answer = (2/3)*(1/4) = 1/6
• 15 years agoHelpfull: Yes(3) No(5)
• 1/2
• 14 years agoHelpfull: Yes(2) No(0)
• After first day only 2/3rd remains. After second day only 3/4th of that remaining from 1st day evaporated. So, final answer = [x-((1/3)x+(2/3)*(3/4))]/x=1/6
• 14 years agoHelpfull: Yes(1) No(0)
• Assume that contents of the container is X
  
  On the first day 1/3rd is evaporated.
  
  (1 - 1/3) of X is remaining i.e. (2/3)X
  
  On the Second day 3/4th is evaporated. Hence,
  
  (1- 3/4) of (2/3)X is remaining
  
  i.e. (1/4)(2/3)X = (1/6) X
  
  Hence 1/6th of the contents of the container is remaining
  
• 11 years agoHelpfull: Yes(1) No(0)