A and B can do a piece of work in 8 days B and C can do the same in 12 days , A and C do the same in 8 days. If A,B,C work together how many day it will complete

• A+B in one day can complete 1/8 work
  B+C in one day can complete 1/12 work
  C+A in one day can complete 1/8 work
  When you add left hand side, you get 2(A+B+C)
  When you add right hand side, you get 1/8 + 1/12 + 1/8 = 1/3
  i.e. 2(A+B+C)=1/3
  A+B+C=1/6 (means A+B+C together do 1/6 work in a day.)
  Therefore, A+B+C will complete work in 6 days.
• 8 years agoHelpfull: Yes(32) No(1)
• LCM(8,12,8)=24
  (A+B) 1 day work=24/8=3
  (B+C) 1 day work=24/12=2
  (A+C) 1 day work=24/8=3
  (A+B+C) 1day work=(3+2+3)/2=4
  A+B+C will complete work in =24/4=6 days
  
• 8 years agoHelpfull: Yes(9) No(1)
• (A+B )1 day work=1/8......eq.(1)
  (B+C )1 day work=1/12......eq.(2)
  (A+C)1 day work=1/8......eq.(3)
  ON ADDING EQ.1,2 &3
  2(A+B+C)=1/8+1/12+1/8=1/3
  (A+B+C )1 day work=1/6
  =6 DAYS
  
  
• 8 years agoHelpfull: Yes(5) No(0)
• (A+B+C)=(2*8*12*8)/((12*8)+(8*8)+(8*12))
  
  Ans will be 6 days
• 8 years agoHelpfull: Yes(2) No(0)
• Take the LCM of 8,12,8=24
  so A+B in one day work=3
  B+C in one day work=2
  A+C in one day work=3
  (A+B)+(B+C)+(A+C)=8
  so 24/8=3
  2(A+B+C)=3
  A+B+C=3*2=6
• 6 years agoHelpfull: Yes(1) No(0)
• =(2*8*12*8)/(8*12+12*8+8*8)
  =1536/(96+96+64)
  =6 days
• 8 years agoHelpfull: Yes(0) No(0)
• (A+B) + (B+C )+(C+A) = > 2(A+B+C) = 1/8 + 1/8 + 1/12
  = 1/4 (1/2 + 1/2 + 1/3 )
  = 1/4 ( 0.5 +0.5 + 1/3 ) => 1/4 (1+ 1/3)
  = 1/4 (4/3) = > 1/3
  A+B+C = 1/2 * 1/3
  = 1/6 ---------> WORK IN 1 DAY
  = 6 ------------> DAYS needed to complete work
• 8 years agoHelpfull: Yes(0) No(0)
• A+B=8
  B+C=12
  A+C=8
  LCM OF 8,12,8 =24=total work
  a+b=3 ,b+c=2,a+c=3
  add above three equations 2(a=b+c)=8
  a+b+c=4
  (A+B+C) working together =24/4
  =6
• 8 years agoHelpfull: Yes(0) No(0)
• a+b=8
  b+c=12
  c+a=8
  lcm=24
  total units=(3+2+3)=8/2=4
  24/4=6 days
• 8 years agoHelpfull: Yes(0) No(0)
• 2xyz/(xy+yz+zx) this is the formula
• 8 years agoHelpfull: Yes(0) No(0)
• lcm of 8,12,8=24
  
  total work =24 units
  a+b =3unit/day
  b+c=2unit/day
  a+c=3 unit/day
  2(a+b+c)=8unit/day
  a+b+c=4unit/day
  
  total work=24units
  
  efficiency=total work/no. of days
  =24/4===6 days
  
  ans==6days
• 7 years agoHelpfull: Yes(0) No(0)
• A+B=1/8
  B+C=1/12
  A+C=1/8
  -------------
  2(A+B+C)=8/24
  =>A+B+C=1/6
  i.e., A,B,C complete the work in 6 days.
• 7 years agoHelpfull: Yes(0) No(0)
• Answer is 6
• 6 years agoHelpfull: Yes(0) No(0)
• A+B=8
  B+C=12 Lcm is 24.
  A+C=8
  Efficience of A+B=3
  B+C=2
  A+C=3
  SO they work together in 24÷8= 3 days
• 6 years agoHelpfull: Yes(0) No(1)