MBA Exam

The HCF of 2 numbers is 119 and their sum is 833. What are the numbers, if they differ by the minimum possible amount?

1) 119 and 545
2) 119 and 714
3) 357 and 476
4) 238 and 545

Read Solution (Total 1)

3) 357 and 476

119x + 119y = 833
=> x + y = 7

They differ by least amount => x = 3 , y = 4

=> Numbers are 357 and 476
11 years agoHelpfull: Yes(0) No(3)

MBA Other Question

Find the remainder 21 ^231 divided by 25.Please post ur Approach. Thnks.

1) 4
2) 16
3) 1
4) none of these
fn ={ 2^n-1 + 1, n is odd 2^n-1 - 1,n is evenfind remainder when f1+ f2 + f3....f100 is divided by 127

1) 0
2) 91
3) 126
4) 3