1- The sum of the ages of abhigail,jennifer and margaret was 52 three year ago.four years ago,jennifer who is a year younger than margaret,was 3/2 times as old as abhigail.the sum of ages of jennifer and margaret two year hence will be?
a- 51
b- 47
c-48
d-49
answer this.

• 3 yrs ago sum = A+j+m=52
  
  present ages sum= A+j+m=61
  
  J=M-1 or M =J+1
  
  J-4 =3/2(A-4)
  
  A= (2 J+4)/3
  
  Substitute all in Second eqn of Sum of present ages
  
  (2j+4)/3 + j + j +1 =61
  
  8j =176
  j=22 present , m= 23 present
  
  after 2 yrs sum = (22+2) +(23+2) =49
• 8 years agoHelpfull: Yes(40) No(6)
• d 49
  
  x+y+z = 52 before 3 yr ago
  four yr ago x+y+z=49 ..............(1)
  condition given is 3/2(z) + 3/2(z) + 1 + z =x+y+z= 49
  
  by solving this z=12
  
  x= 3/2(z) = 3/2 *(12) =18
  y = x+1 =19
  But this is for 4 yrs ago
  So current ages are x=22 and y=23
  after 2 yrs it will be x=24 and y=26
  so x+y=49
  
• 8 years agoHelpfull: Yes(9) No(7)
• 49 is the ryt ans
  
• 8 years agoHelpfull: Yes(7) No(2)
• b 47
  
  x+y+z = 52 before 3 yr ago
  after 3 yr each one age is increased by 3 hence now x+y+z=61
  four yr ego x+y+z= 58 ..............(1)
  condition given is 3/2(z) + 3/2(z) + 1 + z = x+y+z = 58
  
  by solving this z=14
  
  x= 3/2(z) = 3/2 *(14) =21
  y = x+1 =22
  
  x+y = 43 hence 2 yr each one age will increase by 2 so 43+4 == 47
  
  
• 8 years agoHelpfull: Yes(3) No(16)
• ans is d=49
• 8 years agoHelpfull: Yes(3) No(0)
• b) 47
  
  A+J+M=52 ( 3 years ago)
  
  At present Every one age vil b incresed 3, At now A+J+M= 61
  
  4 Years ago A+J+M = 57
  
  Acc. to condition----> A+(1.5 of A)+ (1.5 of A + 1) = 57
  J = As jennifer is 3/2 times old as Abhigali
  M= As Jennifer is a Year is Younger than margaret
  M= ( 1.5 of A )+ 1
  
  On Solving we Get A = 14 i.e, Abhigali
  Jennifer is 1.5 of 14 = 21
  Margaret is J+1 = 22
  
  After 2 years---------> j+M = (21+2) + (22+2)
  = 47
• 8 years agoHelpfull: Yes(2) No(13)
• b 47
  
  x+y+z = 52 before 3 yr ago
  after 3 yr each one age is increased by 3 hence now x+y+z=61
  four yr ego x+y+z= 58 ..............(1)
  condition given is 3/2(z) + 3/2(z) + 1 + z = x+y+z = 58
  
  by solving this z=14
  
  x= 3/2(z) = 3/2 *(14) =21
  y = x+1 =22
  
  x+y = 43 hence 2 yr each one age will increase by 2 so 43+4 == 47
• 8 years agoHelpfull: Yes(1) No(24)
• d.49 as m=19
• 4 years agoHelpfull: Yes(0) No(0)