Ashok bought an article and spent Rs110 on its repair. He then sold it to Bhushan at a profit of 20%. Bhushan sold it to Charan at a loss of 10%. Charan sold it for Rs1188 at a profit of 10%. How much did Ashok pay for the article?
a- 990 rs
b- 890 rs
c- 790 rs
d- 690 rs.

• b. 890 Rs.
  
  If Ashok pays Rs. x for an article, then (x+110)*(120/100)*(90/100)*(110/100)=1188
  On solving x=890
• 8 years agoHelpfull: Yes(60) No(0)
• b) 890
  
  Go with options ,,,, start from middle value....
  
  Ex. 890 is selected..
  
  Solution: 890+ 110 of repair = 1000 ------> Ashok C.P.
  
  Sold to Bhushan for 20% profit i.e., 1000+ 20% of 1000 = 1200
  Bhushan sold to at 10% loss i.e., 1200- 10% of 1200 = 1080
  
  Charan solded at a profit of 10% i.e., 1080 + 10% of 1080 = 1188
  
  Hence that matched to charan sold price......
• 8 years agoHelpfull: Yes(15) No(1)
• 890
  
  
  HE bought at 890 and repaired 110, so totally 1000
  he sold that for 20% profit, 20%(1000)=200 sp=1000+200=1200(profit so +)
  bhusan cost price cp=1200
  he sold it for 10% loss 10%(1200)=120 sp=1200-120=1080 (loss so minus)
  charan cost price cp=1080
  he sold it for 10% profit 10%(1080}=108 sp=1080+108=1188(profit so +)
• 8 years agoHelpfull: Yes(9) No(2)
• answer is 890 as (110+a)*(6/5)*(9/10)*(11/10)=1188=890
• 8 years agoHelpfull: Yes(4) No(0)
• 4000×40/100=1600.profit 4000+1600=5600
  4000×40/100=1600.loss 4000-1600=2400
• 7 years agoHelpfull: Yes(2) No(3)
• Let assume article as x
  110+x*(120/100)*(90/100)*(110/100)=1188
  x=890
• 5 years agoHelpfull: Yes(1) No(0)