Capgemini
Company
Numerical Ability
Permutation and Combination
In how many ways can 5 members be selected out of 10 members,so that any two particular members must always be excluded?
a- 52
b-56
c-60
d-64
Read Solution (Total 15)
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- b-56. since 2 particular members are always excluded then you are actually choosing from 8 members. and the number of ways 5 members are selected is equal to 8C5 which is equal to 56.
- 8 years agoHelpfull: Yes(28) No(0)
- two particular members must be excluded so member=10-2=8
so the answer will be = 8! / 5! (8-5)!=8*7*6*5!/5!*3!=8*7*6/3*2*1=8*7=56 - 8 years agoHelpfull: Yes(8) No(0)
- You have to choose 5 members from 8 .because 2 people always excluded. Therefore 8C5 is equal to 56.
- 8 years agoHelpfull: Yes(5) No(0)
- ans is 56.couple of people selected.so remai9ning 8.8c5-ans is 56
- 8 years agoHelpfull: Yes(1) No(0)
- as 2 members are always excluded then we left with only 8 members and from that 5 members are selected so combination is use -> 8C5= 56
- 8 years agoHelpfull: Yes(1) No(0)
- it will be 8!/(5!*3!)=56
- 8 years agoHelpfull: Yes(0) No(0)
- exclude 2 out of 10 i.e.., 8
select 5 out of 8
8c5 = 56 - 8 years agoHelpfull: Yes(0) No(0)
- b-56
Since two members should be excluded total members are 8.
from eight we can select 5 as 8C5 which is 56. - 8 years agoHelpfull: Yes(0) No(0)
- 2 ppl are excluded always ie 8C5 = 56
- 8 years agoHelpfull: Yes(0) No(0)
- 8c2 =56
Because 2 people are excluded in 10 - 8 years agoHelpfull: Yes(0) No(0)
- 2 r always excluded so it is 8C5 =56
- 8 years agoHelpfull: Yes(0) No(0)
- Two members always be excluded means 8 members should be availablle ..So we can select 5 members from 8 members (ie) 8c5=56
- 8 years agoHelpfull: Yes(0) No(0)
- B. 56
since, 2 members must be excluded so remaining member is only 8
so,
8C6 = 8! / 3! = 56 - 8 years agoHelpfull: Yes(0) No(0)
- 2 mans always excluded then there are 8 members available, then select 5 members out of 8 .
so the possible ways are 8c5.
- 8 years agoHelpfull: Yes(0) No(0)
- 8 c 5=56.
- 8 years agoHelpfull: Yes(0) No(0)
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