In how many ways 8 members can be selected for a team such that women constitute at least 50% of the team from a group of 8 men and 8 women.

• in all we have to choose 8 members from total
  where at least 50% women are present
  so we have cases like
  4 women and 4 men = 8C4 * 8C4 = 70*70=4900
  5 women and 3 men = 8C5*8C3 = 56*56=3136
  6 women and 2 men = 8C6*8C2=28*28=784
  7 women and 1 man = 8C7*8C1=8*8=64
  8 women and 0 man = 8C8 =1
  adding all the 4 values above obtained we have
  8885 ways
• 7 years agoHelpfull: Yes(12) No(2)
• 4w=8c4+8c4=140
  5w=8c5+8c3=112
  6w=8c6+8c2=56
  7w=8c7+8c1=16
  8w=1
  total=325
• 7 years agoHelpfull: Yes(5) No(8)
• 8101 ways.
• 8 years agoHelpfull: Yes(0) No(3)