Elitmus
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if log xy^2 =a, log x^3y =b,find log y/log x=??
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- log xy^2 =a
log x+log y^2=a
logx+2logy=a
logx=a-2logy------------(1)
logy=a-logx/2----------(2)
logx^3+logy=b
3logx+logy=b--------------(3)
3(a-2logy)+logy=b-----(from 1)
3a-6logy+logy=b
3a-b=5logy
logy=3a-b/5
3logx+a-logx/2=b
6logx+a-logx=2b
5logx=2b-a
logx=2b-a/5
logy/logx=3a-b/2b-a-----------
- 8 years agoHelpfull: Yes(7) No(0)
- b-a/3a-2b
- 8 years agoHelpfull: Yes(1) No(1)
- a=log x+2log y
b=3log x+log y
substituting the values of log x and log y from above equations we get
log x=(2b-a)/5
log y=(3a-b)/5
so, log y/log x= 3a-b/2b-a - 8 years agoHelpfull: Yes(1) No(0)
- was there any option like (a-b) [e^(a-b)/b]+2 ?
if yes then this is the answer - 8 years agoHelpfull: Yes(0) No(1)
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