if log xy^2 =a, log x^3y =b,find log y/log x=??

• log xy^2 =a
  log x+log y^2=a
  logx+2logy=a
  logx=a-2logy------------(1)
  logy=a-logx/2----------(2)
  
  logx^3+logy=b
  3logx+logy=b--------------(3)
  
  3(a-2logy)+logy=b-----(from 1)
  3a-6logy+logy=b
  3a-b=5logy
  logy=3a-b/5
  
  3logx+a-logx/2=b
  6logx+a-logx=2b
  5logx=2b-a
  logx=2b-a/5
  
  logy/logx=3a-b/2b-a-----------
  
  
• 8 years agoHelpfull: Yes(7) No(0)
• b-a/3a-2b
  
• 8 years agoHelpfull: Yes(1) No(1)
• a=log x+2log y
  b=3log x+log y
  
  substituting the values of log x and log y from above equations we get
  
  log x=(2b-a)/5
  log y=(3a-b)/5
  
  so, log y/log x= 3a-b/2b-a
• 8 years agoHelpfull: Yes(1) No(0)
• was there any option like (a-b) [e^(a-b)/b]+2 ?
  if yes then this is the answer
• 8 years agoHelpfull: Yes(0) No(1)