Two trains for Y leave X at 6.30am and 7.40am and travel at 30km/hr and 40 km./he respectively. How many kms from A will the trains meet?

• Formula:
  When two train are leaving the station at t1and t2 time and therir speed is s1and s2then they will meet at distance
  
  =(t2-t1)*(s1*S2)/(S2-S1)
  =7/6*(30*40)/(40-30)
  =140km
• 8 years agoHelpfull: Yes(6) No(0)
• 140 km.
  
  *As in the question it is given train leave X for Y, so if it is asked to calculate the distance from X when the train meet, then
  Distance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours=30*7/6=35 km., So train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr. Hence time taken=35/10=3.5 hours or 3 hours 30 minutes
  So distance from X =Distance traveled by 2nd train in 3 hr. 30 min or by 1st train in (1 hr 10 min+3 hr 30 min) 4 hr 40 min.=40*3.5=140 km
• 8 years agoHelpfull: Yes(3) No(1)