what will be the minimum value of X in X^3-7X^2+11X-5 so we get a positive number.
a) 4
B) 5
c) 8

• Answer is 5
  
• 8 years agoHelpfull: Yes(10) No(9)
• Answer is 8 because according to option verification
  If we substitute 4 in the given equation then it becomes
  (4)^3-(7*(4)^2)+(11*4)-5=-9
  then substitute 5 in the equation
  (5)^3-(7*(5)^2)+(11*5)-5=0
  then substitute 8 in the equation
  (8)^3-(7*(8)^2)+(11*8)-5=147 which is a positive integer.
  
• 8 years agoHelpfull: Yes(8) No(2)
• c) 8
  Because other 2 options wet get zero as ans
• 8 years agoHelpfull: Yes(7) No(6)
• c) 8 becz other two options get negative
• 8 years agoHelpfull: Yes(7) No(0)
• c) 8. Because 0 is neither negative nor positive.
  
• 8 years agoHelpfull: Yes(3) No(0)
• Ans=8
  x^2(x-7)+11*x-5
  x must be >=7
• 8 years agoHelpfull: Yes(2) No(0)
• put x=4,so that eqn will be 64-102+44-5=1,so answer will be 4
• 8 years agoHelpfull: Yes(2) No(9)
• 4
  enter the 4 value in given eq
• 8 years agoHelpfull: Yes(2) No(1)
• Answer must be 11/3 for the minimum value of f(x) =x^3-7x^2+11x-5
  f'(x)=3x^2-14x+11
  so min and max at either x=1 or x=11/3
  f''(x)=6x-14
  at x=1 f''(x)0 hence minimum value
  thus answer must be 11/3
• 8 years agoHelpfull: Yes(2) No(0)
• 5 is the answer
  
• 8 years agoHelpfull: Yes(1) No(5)
• x^3-7x^2+11X-5......1
  sub 4 in eq 1
  we get minimum positive value
• 8 years agoHelpfull: Yes(0) No(16)
• answer is 8 because on valuse of X=1 and 5 we get zero ans. So for positive number obviously the number should be greater than 5. So here 8>5
• 8 years agoHelpfull: Yes(0) No(0)
• (x-5)(x-1)(x-1)
  the min value is 1
• 8 years agoHelpfull: Yes(0) No(1)
• 8^3-7*8^2+11*8-5=147
  it is a positive number
  other numbers are getting 0 and -9
• 8 years agoHelpfull: Yes(0) No(0)
• answer is 5
• 7 years agoHelpfull: Yes(0) No(0)