CTS
Company
Numerical Ability
Arithmetic
One third of a two digit number exceeds its one fourth by 7. What is the sum of digits of the number?
Options
1) 72
2) 84
3) 15
4) 12
Read Solution (Total 4)
-
- X/3=x/4 +7
=84
By summing the two digits 8+4=12
Optn 4 - 8 years agoHelpfull: Yes(7) No(2)
- 1/3(10x+y) - 1/4(10x+y)=7
[(10x+y)]/12=7
10x+y=84 - 8 years agoHelpfull: Yes(7) No(1)
- first let the number be x
so x/3 - x/4 = 7
x/12 = 7
x=84
number is 84 and sum of digits is 8 + 4 = 12 - 7 years agoHelpfull: Yes(1) No(1)
- 4. 12
Let number be x.
Then, x/3-x/4=7
=> x = 84
Thus sum of digits of 84 is 12(8+4). - 5 years agoHelpfull: Yes(0) No(0)
CTS Other Question