A, B and C can do a work in 24, 32 and 60 days respectively. They start working together. A left after 6 days B left after 8 days. how many more days are required to complete the whole work?
a) 30
b) 25
c) 22
d) 20
e) None of these

• (A+B+C)'s 1 Day work = (1/24+1/32+1/60) ;- LCM of 1/24 + 1/32 + 1/60 is (20+15+8)/480
  = 43/480
  A left after 6 days means = 6*(43/480) = 258/480
  B left after 8 days means here 6 days already worked with A so only 2 days extra worked compared to A
  i.e.. 2(1/32+1/60) = 2(15+8)/480 = 46/480
  remaining work = 1-[(258/480)+(46/480)]
  = 1-[304/480]
  = 1-[19/30]
  = 11/30
  C can do 11/30 remaining work
  C's 1 Day work = 1/60
  11/30 can complete in (11/30)*60 = 22 Days
• 8 years agoHelpfull: Yes(11) No(2)
• 6day=6*(43/480)=43/80
  8day =8*(23/480)=23/60
  total 14 day=43/80+23/60=221/240
  remaining work=1-221/240=19/240
  c will do=19/240-1/60=1/8
  so,c will take 8 days
  total=8+6+8=22days
  
• 8 years agoHelpfull: Yes(1) No(5)