Walking at ¾ of his usual speed a man is 16 min late for his office. the usual time taken by him to cover that distance is
a) 48 minutes
b) 60 minutes
c) 42 minutes
d) 62 minutes
e) None

• Distance = Speed * Time
  Here distance is constant
  therefore s1*t1=s2*t2
  where s1 is his normal speed let it be =x
  t1 = t
  s2=3x/4
  t2=t+16(as it take 16 min more)
  now s1*t1=s2*t2
  x*t = (3x/4)(t+16)
  4t - 3t =48 min
  
  :- time t = 48 min
• 8 years agoHelpfull: Yes(13) No(0)
• 3/4x(16+t)=x+t
  t=48
• 8 years agoHelpfull: Yes(3) No(0)
• time=distance/speed
  4/3 of usual time - usual time=16
  usual time/3=16
  usual time=16*3= 48min
• 8 years agoHelpfull: Yes(3) No(0)
• formula used:- (xt)/(y-x)
  X/Y =3/4
  t=16 (3*8)/(4-3)
  ans = 48
• 8 years agoHelpfull: Yes(0) No(0)
• 48 min is correct ans
• 8 years agoHelpfull: Yes(0) No(0)
• Usual speed = x km/h
  Distance = d km
  Usual and 3/4 of usual walking time difference = 16
  So, (4d/3x) - (d/x) = 16
  => d/x = 48 minutes
  d/x = Usual time taken by the person.
• 5 years agoHelpfull: Yes(0) No(0)