out of 7 consonant and 4 vowels, how many words of 3 consonant and 2 vowels can be formed?

ans:25200

please someone explain this

• 
  
  Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)
  
  = inline {color{Black}(7C_3{}times 4C_2{})}
  
  = 210.
  
  Number of groups, each having 3 consonants and 2 vowels = 210.
  
  Each group contains 5 letters.
  
  Number of ways of arranging 5 letters among themselves
  
  = 5!
  
  = 120
  
  Required number of ways = (210 x 120) = 25200.
• 8 years agoHelpfull: Yes(0) No(0)
• to select 3 cons and 2 vow is =7c3 x 4c2=35 x 6
  now there are 5 letter which can be arrange as= !5=120
  so total prob is =120 x 35 x 6=25200
• 8 years agoHelpfull: Yes(0) No(0)