find n if (2^228/2^n)=512

• 2^228=512*2^n
  2^228=2^9*2^n
  2^228=2^(9+n)
  228=9+n
  n=228-9
  n=219
  
• 8 years agoHelpfull: Yes(14) No(0)
• 2^228/2^n=512
  2^228=2^9*2^n
  Bases same power add
  228=9+n
  n=228-9
  n=219
• 8 years agoHelpfull: Yes(3) No(0)
• (2^228/2^n) = 512 = 2^9
  => 2^228 = 2^n+9
  => n+9 = 228
  => n = 219.
  therefore, the required value of n is 219.
• 8 years agoHelpfull: Yes(1) No(0)
• 2^228=512*2^n
  2^228=2^9*2^n
  2^228=2^(9+n)
  228=9+n
  n=228-9
  n=219 ans
• 8 years agoHelpfull: Yes(1) No(0)
• Since,512=2^9
  So,by cross multiplication..2^9 * 2^n=2^(9+n)
  and left side is:2^228.
  so,becauz of same base both side...the power goes equal..so 9+n=228
  n=228-9=219..Ans
• 8 years agoHelpfull: Yes(1) No(0)
• 2^228=512^1*2^n
  228=1+n
  n=227
• 8 years agoHelpfull: Yes(0) No(1)
• n=22 solve 2^(228-n)=2^6
• 8 years agoHelpfull: Yes(0) No(1)
• 2^228/2^n = 512
  2^228-n = 2^9
  bases same so we equate the sides
  
  228-n = 9
  n = 228-9
  n=219
• 8 years agoHelpfull: Yes(0) No(0)
• 2^228/2^n=512
  2^(228-n) = 2^9
  228-n=9
  n=228-9
  n=219
• 8 years agoHelpfull: Yes(0) No(0)
• 219
  2^228-n=2^9
  228-n=9
  n=219
• 8 years agoHelpfull: Yes(0) No(0)
• 228-n=9;
  
  
• 8 years agoHelpfull: Yes(0) No(0)
• 2^(228-219)=2^9=512
  so 219 is ans
• 8 years agoHelpfull: Yes(0) No(0)
• 2^228-n = (2^3)^3
  228-n = 9
  n = 219
• 8 years agoHelpfull: Yes(0) No(0)
• n=219
  (2^228/2^n)=512
  (2^228/2^n)=2^9
  2^n=(2^228/2^9)
  n=228-9
  n=219
• 8 years agoHelpfull: Yes(0) No(0)
• n=219.
  (2^228)/512=2^n
  (2^228)/(2^9)=2^219
  2^219=2^n
  n=219
• 8 years agoHelpfull: Yes(0) No(0)
• 2^228-n=2^9
  228-n=9
  n=228-9=219
• 7 years agoHelpfull: Yes(0) No(0)
• (2)^228-n=2^9
  228-n=9
  n=219
• 7 years agoHelpfull: Yes(0) No(0)
• 2^n=512/2^228
  nlog2=log(512/2^228)
  n=219
• 7 years agoHelpfull: Yes(0) No(0)
• 2^228 - n = 2^9
  
  228-n = 9
  
  n = 228-9 = 219
• 7 years agoHelpfull: Yes(0) No(0)
• 220 as 2^8=512
• 7 years agoHelpfull: Yes(0) No(0)
• 2^(228-n)=2^9
  take log base 2 at both sides
  228-n=9
  n=228-9
  n=219
• 7 years agoHelpfull: Yes(0) No(0)
• given 2^228/2^n=512
  2^(228-n)=512
  2^(228-n)=2^9
  
  228-n=9
  n=228-9=219
• 7 years agoHelpfull: Yes(0) No(0)
• answer is219
• 7 years agoHelpfull: Yes(0) No(0)
• ans= n-1+n-2=2n-3.
  First detective will call all other detectives : Eg: 1st detective calls 2nd,3rd,....nth, so n-1 calls, by this 1st and the nth detective knows all the information. Now 1st detective, since he knows all the information will call the n-2 detectives and share the info with them. hence n-1+n-2 =2n-3 calls.
• 7 years agoHelpfull: Yes(0) No(0)
• 2^(228-n)=2^9
  bases are equal,so powers will be:
  228-n=9
  n=219
• 7 years agoHelpfull: Yes(0) No(0)
• (2^228/2^n)=512
  By using reverse logic,we can solve it
  formula:a^m*a^n=a^(m+n)
  2^9=512
  228-9=219
  so 2^n=2^219
  answer:n=219
• 6 years agoHelpfull: Yes(0) No(0)
• 2^228/2^n we can write this as 2^(228-n) which should give the result as 512.
  and 512 is 2^9 .
  so 228-n=9
  => n=228-9
  => n=219 .
  so we get 2^228/2^219 result is 512 .
• 6 years agoHelpfull: Yes(0) No(0)
• 219
  2^9=512
• 6 years agoHelpfull: Yes(0) No(0)
• 2^219
  2^228/2^n=2^9
  2^228=2^9 .2^n
  2^228=2^(9+n)
  =>228=9+n
  =>n=219
• 5 years agoHelpfull: Yes(0) No(0)
• 512=2^9
  Therefore 228-9=219
  
  
  
  
  "
• 5 years agoHelpfull: Yes(0) No(0)
• 512= 2^9
  n=219
• 5 years agoHelpfull: Yes(0) No(0)
• 2^(228-n) = 2^9
  =>228-n = 9
  =>n=228-9
  =>n=219.
• 2 years agoHelpfull: Yes(0) No(0)