CTS
Company
Numerical Ability
Profit and Loss
The cost of 7 tables and 12 chairs is Rs 48,250. What is the cost of 21 tables and 36 chairs?
A) Rs 96,500
B) Rs l,25,500
C) Rs l,44,750
D) Cannot be determined
E) None of these
Read Solution (Total 8)
-
- ans : C
(7T+12C=48250 then 21T+36C=?)
7T*3=21T
12C*3=36C
so 48250*3=1,44,750 - 8 years agoHelpfull: Yes(16) No(0)
- 3T+12C = 48,250----(1)
21T+36C = ?
multiply eq (1) with 3
i.e,, 3(7T+12C) = 48,250*3
21T+36C = 1,44,750/- - 8 years agoHelpfull: Yes(6) No(0)
- 7T+12C = 48,250----(1)
21T+36C = ?
multiply eq (1) with 3
i.e,, 3(7T+12C) = 48,250*3
21T+36C = 1,44,750/- - 8 years agoHelpfull: Yes(3) No(0)
- Ans:C)-144750,bcz if 7 tables nd12 chairs cost 48250, triple of 7 tables ND 12 chairs which r (7*3=21) tables ND (12*3=36) tables wud cost triple of 48250 which is (3*48250=144750)
- 8 years agoHelpfull: Yes(0) No(0)
- since number of table & chair is 3 times so 48250 x 3 = 144750 (c)
- 8 years agoHelpfull: Yes(0) No(1)
- 7T+12C=48250
then
21T+36C=x
solve this two equation
and get x=144750
x= - 8 years agoHelpfull: Yes(0) No(0)
- C we multiply it by 3
- 7 years agoHelpfull: Yes(0) No(0)
- Let the cost of one table be Rs.T and the Cost of Chair be Rs.C.
Then, According to the question,
7T+12C = 48250
Multiply by 3, we will get, 21T + 36C = 1,44,750
So, the correct answer is option C - 5 years agoHelpfull: Yes(0) No(0)
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