ria,tia,gia,sia and dia hav 4 fruits each.the fruits are either bananas or grapes.the no :of bananas with each is different and hence,so is d no :of grapes .the sum of d no:of grapes with ria and sia is half the total no:of bananas.dia has the least no:of bananas.wt is the difference between no:of bananas with gia and no:of grapes with tia ?

• gia tia ria sia dia
  
  bananas 4 3 2 1 0
  
  grapes 0 1 2 3 4
  
  as ria and sia total no of grapes=half of total no of bananas
  as 1(no of grapes if we expect it real sia) + 4 = 5 also 3+2
  but dia has least no of bananas i.e 0 so its 4(no of grapes) get cancelled
  and hence for gia and tia 4-1=3 and 3-0=3
  so the answer is 3
• 7 years agoHelpfull: Yes(12) No(3)
• ans:- the difference is 3
• 8 years agoHelpfull: Yes(6) No(18)
• Ria=gg+bb
  tia=ggg+b
  gia=g+bbb
  Sia=gg+bb
  dia=gggg
  
  The difference=3-3=0.
• 7 years agoHelpfull: Yes(4) No(1)
• ria=gg+bb
  tia=g+bbb
  gia=bbbb
  sia=ggg+b
  dia=gggg
  so,the ans =3
  
• 7 years agoHelpfull: Yes(2) No(1)
• Ria=gg+bb
  tia=ggg+b
  gia=g+bbb
  Sia=gg+bb
  dia=gggg
  3 is the answr
  
• 7 years agoHelpfull: Yes(0) No(2)