elitmus Exam Numerical Ability Number System

a series of natural number 1+2+3+4+5+6+7+8+9+10 is divisibel by 11 so we has to find how many such series is possible upto n where n is less than 1000.
a.90
b.99
c.180
d 96

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elitmus Other Question

what is the minimum value of f(x) where
f(x)=(logax+logbx+logcx) and a>b>c>1..
option
a. 3
b 2
c 1
d 4
a number has only k and k-2 factor off a number n the factor 1 and n is not consider so what is possibel..
a.n+1 is perfect square.
b.n-1 is a odd or prime number.
c. n+1 is a even number
d. all of above