The sum of series 1+1(1+1/n)+3(1+1/n)2+…. Is equal to

• 1+1,3,5,7............(1+1/n)1,2,3,.......
  1+(1+(n-1)2)(1+1/n)n
  1+(2n-1)(n+1)
  1+2n^2+2n+n-1
  2n^2+n
  n(2n+1)
• 7 years agoHelpfull: Yes(2) No(4)
• 1+1,3,5,7___(1+1/n)1,2,3,4,5___
  
  1+(1+(n-1)2)(1+1/n)n
  
  1+(2n-1)(n+1/n)(n)
  
  1+(2n-1)(n+1)
  
  1+2n*n+n-1
  
  2n*n+n ANS
• 7 years agoHelpfull: Yes(1) No(1)
• we can write in general form
  1+sum((2n-1)(1+1/n)n)
  1+sum(2n^2+n-1)
  1+[2[n(n+1)(2n+1)]/6]+[n(n+1)/2]-n
• 7 years agoHelpfull: Yes(1) No(0)
• s= 1+(1+1/n)+3(1+1/n)^2+..........
  (1+1/n)s= 0+(1+1/n)+(1+1/n)^2+3(1+!/n)^3+......
  _
  ------------------------------------------------------------------------------------------------
  -s/n=1+2(1+1/n)^2(-1/n)
  then
  s=2(n+1)^2-1
• 7 years agoHelpfull: Yes(0) No(0)
• how many terms and what is n
  
• 7 years agoHelpfull: Yes(0) No(0)
• 2n2 + 3n + 2
• 7 years agoHelpfull: Yes(0) No(1)