A picks a no from the bag where the bag consists of no from {1,2....23} and puts it in the same bag. Now another person B picks a no from the bag.Find the probability that A has picked a greater no than B??
A)22/23 B) 1/10 C)1/2 D)none

• 
  If Ram draws 1, then Sam can draw anything from 2 to 23 = 22 ways
  If Ram draws 2, then Sam can draw anything from 3 to 23 = 21 ways
  . . . .
  . . . .
  If Ram draws 23, Sam has no option = 0 ways.
  Total required ways = 22 + 21 + 20 + . . . . + 0 = 22×232 = 253
  Total ways of drawing two cards = 23×23
  Required probability = 253/529=11/23
• 8 years agoHelpfull: Yes(24) No(5)
• 22/23 is the answer.
  we need to take the probability of number taken by A should be greater than B's number.
  If A takes 23 then B's number would be between 1 to 22
  if A takes 22 then B's number would be between 1 to 21
  and so on.
  at last if A takes 2 as a number then B's number should be 1.
  In this way the cases in which A takes the number and it is greater than B are 22.
  and total numbers are 23. So, the probability is 22/23.
  Correct me if am wrong.
• 5 years agoHelpfull: Yes(2) No(0)
• ans- d
  if B picks 1 then prob. = 22/23
  if B picks 2 then prob. = 21/23
  similarly if B picks 22 then prob. = 1/23
  so, overall prob. = 22/23 X 21/23 X...X 1/23
  = 22! / (23 ^ 23)
• 8 years agoHelpfull: Yes(1) No(10)